Matches in DBpedia 2016-04 for { ?s ?p "Catherine Vasa (Swedish: Katarina Gustavsdotter Vasa; 6 June 1539 – 21 December 1610) was a Swedish princess, and the Countess consort of East Frisia as the spouse of Edzard II, Count of East Frisia. She was the oldest daughter of Gustav Vasa and Margareta Leijonhufvud. She was the eutonomous Regent of Berum and Norden in Ostfriesland (East Frisia) from 1599 to 1610."@en }
Showing triples 1 to 4 of
4
with 100 triples per page.
- Catherine_Vasa abstract "Catherine Vasa (Swedish: Katarina Gustavsdotter Vasa; 6 June 1539 – 21 December 1610) was a Swedish princess, and the Countess consort of East Frisia as the spouse of Edzard II, Count of East Frisia. She was the oldest daughter of Gustav Vasa and Margareta Leijonhufvud. She was the eutonomous Regent of Berum and Norden in Ostfriesland (East Frisia) from 1599 to 1610.".
- Q2211749 abstract "Catherine Vasa (Swedish: Katarina Gustavsdotter Vasa; 6 June 1539 – 21 December 1610) was a Swedish princess, and the Countess consort of East Frisia as the spouse of Edzard II, Count of East Frisia. She was the oldest daughter of Gustav Vasa and Margareta Leijonhufvud. She was the eutonomous Regent of Berum and Norden in Ostfriesland (East Frisia) from 1599 to 1610.".
- Catherine_Vasa comment "Catherine Vasa (Swedish: Katarina Gustavsdotter Vasa; 6 June 1539 – 21 December 1610) was a Swedish princess, and the Countess consort of East Frisia as the spouse of Edzard II, Count of East Frisia. She was the oldest daughter of Gustav Vasa and Margareta Leijonhufvud. She was the eutonomous Regent of Berum and Norden in Ostfriesland (East Frisia) from 1599 to 1610.".
- Q2211749 comment "Catherine Vasa (Swedish: Katarina Gustavsdotter Vasa; 6 June 1539 – 21 December 1610) was a Swedish princess, and the Countess consort of East Frisia as the spouse of Edzard II, Count of East Frisia. She was the oldest daughter of Gustav Vasa and Margareta Leijonhufvud. She was the eutonomous Regent of Berum and Norden in Ostfriesland (East Frisia) from 1599 to 1610.".